All categories

2 years ago

Can somebody help me? Preferably with working out if possible

Mathematics

2 answers:

saveliy_v [14]2 years ago

6 0

Answer:

d=9

Step-by-step explanation:

First we can do same to both side by adding 2 to both sides:

1=1/3d-2

+2 +2

--------------

3 = 1/3d

Then to get the d on its own, we multiply each side by 3

3=1/3d

*3 *3

---------

9=d

Our final answer is 9

Kamila [148]2 years ago

3 0

Answer:

d = 9

Step-by-step explanation:

Given

1 = $\frac{1}{3}$ d - 2 ( multiply through by 3 to clear the fraction )

3 = d - 6 ( add 6 to both sides )

9 = d

You might be interested in

What number is 80% of 660?

ddd [48]

Answer:

528

Step-by-step explanation:

(80:100)*660 =

(80*660):100 =

52800:100 = 528

Now we have: 80 percent of 660 = 528

7 0

3 years ago

2, -4, 8, -16, . . . find the next two numbers in the pattern and describe the pattern.

il63 [147K]

The next numbers are 32 and -64 the pattern multiplies by -2

6 0

2 years ago

Please answer and put how

muminat

6 + m/4 = 3 (subtract 6 from both sides)
m/4 = -3 (multiply both sides by 4)
m = -12

Can plug in to original equation to check work:
6 - 12/4 = 3
6 - 3 = 3
3 = 3

The answer m = -12 checks out

3 0

2 years ago

Read 2 more answers

Three functions are given below: f(x), g(x), and h(x). Explain how to find the axis of symmetry for each function, and rank the

LuckyWell [14K]

Answer:

1. x=8 is the line of symmetry for f(x) = -4(x − 8)2 + 3

2. x=-2 is the line of symmetry of g(x) = 3x2 + 12x + 15

3. x=3 is the line of symmetry of h(x), shown in the graph.

Step-by-step explanation:

To find the line of symmetry of a vertical parabola (second degree polynomial), find the value of x that sets the squared term to zero. This is a vertical line passing through the vertex of the second degree function.

1. f(x) = -4(x − 8)2 + 3

setting x=8 will give f(8) = 3, so x=8 is the line of symmetry

2. g(x) = 3x2 + 12x + 15

here, we need to complete the squares,

g(x) = 3x2 + 12x + 15

g(x) = 3(x^2+4x+5)

g(x) = 3(x^2 + 2(2x) +4 +1)

g(x) = 3((x+2)^2 +1)

So setting x=-2 will anihilate or cancel the squared term, therefore

x= -2 is the line of symmetry.

3. the curven shown in graph,

we see that the vertex is at x=3, so x=3 is the line of symmetry.

5 0

3 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

2 years ago