Answer:
1/30
Step-by-step explanation: There are 30 students 19 play instr, 10 play spor,
8 who do both. Their is one student that was left out so the answer is 1/30
Answer:
Look below.
Step-by-step explanation:
For further reference I suggest looking at Khan academy videos of this.
A. log8 5/9
B. log9 4
C. log6 2^3
For zeroes of r1,r2,r3, the factors of the function, f(x) are
(x-r1)(x-r2)(x-r3)
zeroes of -3,-5,2
(x-(-3))(x-(-5))(x-2)=
(x+3)(x+5)(x-2)
f(x)=(x+3)(x+5)(x-2)
expanded
f(x)=x³+6x²-x-30
Answer:
There were 76 childrens and 14 adults.
Step-by-step explanation:
Since the group has a total of 90 children and adults, then the sum of the number of adults with the number of children must be equal to 90 as shown below:
children + adults = 90
Since the total cost for their tickets was 548 then the number of children multiplied by the price of their ticket summed by the number of adults multiplied by the price of their ticket must be equal to that. We have:
5*children + 12*adults = 548
With these two equations we have a system of equations shown below:
children + adults = 90
5*children + 12*adults = 548
In order to solve this we will multiply the first equation by -5, and sum both equations we have:
-5*children - 5*adults = -450
5*children + 12*adults = 548
7*adults = 98
adults = 98/7 = 14
children + 14 = 90
children = 90 - 14 = 76
There were 76 childrens and 14 adults.
