let's firstly convert the mixed fractions to improper fractions and then subtract, bearing in mind that the LCD of 4 and 2 is 4.
![\bf \stackrel{mixed}{8\frac{3}{4}}\implies \cfrac{8\cdot 4+3}{8}\implies \stackrel{improper}{\cfrac{35}{4}}~\hfill \stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{35}{4}-\cfrac{15}{2}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{(1)35~~-~~(2)15}{4}}\implies \cfrac{35-30}{4}\implies \cfrac{5}{4}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%204%2B3%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B35%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B7%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B7%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B15%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B35%7D%7B4%7D-%5Ccfrac%7B15%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%204%7D%7D%7B%5Ccfrac%7B%281%2935~~-~~%282%2915%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B35-30%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B4%7D)
Answer:
164 sq. meters
Step-by-step explanation:
So to make it easier, you can break the shape up in a smaller shape. So now it'll look like 2 big rectangles on each side with a small rectangle in the middle. Now you can find the area.
For the big rectangle on the left:
5 × 15 = 75
For the big rectangle on the right:
5 × 15 = 75
For the small rectangle in the middle:
It doesn't say what the length is but if you subtract 8 from 15, that's what the length will be.
15 - 8 = 7
L = 7
7 × 2 = 14
Now add all the areas up.
75 + 75 + 14 = 164
From least to greatest it would be: 1.2, 1.23, 2.31, 3.2 I believe hope that helped
Answer:
This is frankly impossible.
Step-by-step explanation:
What you have given me are three x-intercepts. And it is impossible for a quadratic function to have more than two roots. However, if this was an cubic function, we could multiply (x+5)(x-1)(x-4) which results in the equation which simplifies into x^3 -21x + 20. However, this is a cubic function, not a quadratic function, so something must be wrong with this problem all together.
A and C should be the answer, hope this helps
