Answer:
The weights of each cylinder and prism are 3 and 4 ounces, respectively.
Step-by-step explanation:
Let be 
and 
the masses of a cylinder and a prism, measured in ounces, respectively. After a careful reading of the statement we get the following linear equations by interpretation:
i) <em>She found that 4 cylinders and 5 prisms weigh 32 ounces:</em>
(Eq. 1)
ii) <em>And that 1 cylinder and 8 prisms weigh 35 ounces:</em>
(Eq. 2)
Now we solve the system of linear equations algebraically:
From (Eq. 2):
(Eq. 2) is (Eq. 1):
From (Eq. 2):
The weights of each cylinder and prism are 3 and 4 ounces, respectively.
The correct answer is:
[A]: "
" .
______________________________________________________<u>Note</u>: "3/4" = "6/8" = "15/20" .
______________________________________________________
Answer:
The error she made was that she was adding x and 2.75. She should subtract 2.75 from x.
Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.
Step-by-step explanation:
The error she made was that she was adding x and 2.75.
She should write the equation as 8 (x - 2.75) = 78; as she spends $2.75 to make a necklace.
By using the correct equation: 8 (x - 2.75) = 78
=> 8x - 22 = 78
=> 8x = 78 + 22
=> 8x = 100
=> x = 100/8
=> x = 12.5
Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.
Hope this helps you.
Answer:
TSA=6a²
TSA=6*17*17=1734 mm²
Step-by-step explanation:
Answer:
<em>A=3 and B=6</em>
Step-by-step explanation:
<u>Increasing and Decreasing Intervals of Functions</u>
Given f(x) as a real function and f'(x) its first derivative.
If f'(a)>0 the function is increasing in x=a
If f'(a)<0 the function is decreasing in x=a
If f'(a)=0 the function has a critical point in x=a
As we can see, the critical points may define open intervals where the function has different behaviors.
We have
Computing the first derivative:
We find the critical points equating f'(x) to zero
Simplifying by -6
We get the critical points
They define the following intervals
Thus A=3 and B=6
