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3 years ago

Write a recursive rule for the sequence -5, 10, -20 , 40 -80

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

4 0

For every negative number, you multiply that number by two, and then negative one. For example: -5*2= -10. -10*-1=10.

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In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

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$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

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$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

4 years ago

40x=10x^2+41 Identify the number of solutions and their types using the discriminant

nydimaria [60]

Number of solutions: no roots

Type of solution: Not Real

Step-by-step explanation:

We need to identify the number of solutions and their types using the discriminant.

We are given: $40x=10x^2+41\\$

Rearranging:

$40x-10x^2-41=0\\10x^2-40x+41=0$

Discriminant can be found by: $b^2-4ac$

where b=-40, a=10 and c=41

Putting values:

$b^2-4ac\\=(-40)^2-4(10)(41)\\=1600-1640\\=-40\\$

So, Discriminant is -40

If the discriminant is less than zero i.e -40 then there are no real roots.

So, Number of solutions: no roots

Type of solution: Not Real

Keywords: discriminant

Learn more about discriminant at:

#learnwithBrainly

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3 years ago

Which expression is equivalent to sec2x − 1?

hichkok12 [17]

tan^2(x) is the answer.

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3 years ago

I need helping solving -3z+7=-7-10z

Tpy6a [65]

-3z + 7 = -7 - 10z

Add 10z to both sides

7z + 7 = -7

Subtract 7 from both sides

7z = -14

Divide by 7

Z = -2

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4 years ago

Read 2 more answers

I need to know the steps on how to do it

Sergeu [11.5K]

You need help with what problem

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3 years ago