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3 years ago

NEED HELP ASAP!!! THX Determine if the two figures are congruent and explain your answer. Attachment

Mathematics

2 answers:

Norma-Jean [14]3 years ago

8 0

I need the attachment that goes with it

maxonik [38]3 years ago

6 0

Cant do it without the attachment

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Solve the following proportion: (round to the nearest tenths place if necessary)

romanna [79]

Solution:

Note that:

4/7 = 10/x

To find the solution to the proportion, we will need to simplify the equation (4/7 = 10/x)

4/7 = 10/x
=> 4x = 70
=> x = 70/4 = 35/2 = 17.5.

Hoped this helped!

8 0

2 years ago

Read 2 more answers

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago

(20 points)

vladimir1956 [14]

Answer:

Step-by-step explanation:

Slope is the same(x) therefore they are parallel

3 0

4 years ago

A circle whose center is the origin passes through the point (-5,12). Which point also lies on this circle?

schepotkina [342]

The answer is B(11, 2sqrt(12) )
proof

the main equation of the circle is (x-x1)²+(y-y1)²=R²
where C(x1, y1) is the center
so if the center is the origin, it is O(0,0), and the equation becomes
 (x)²+(y)²=R²
and the circle passes through the point (-5,2) so we can write
(-5)²+12²=R², it implies R= sqrt(25+144)=sqrt(169)=13

and for B(11, 2sqrt(12) ) 11²+ (2sqrt(12))²= 121 + 48= 169= 13
it is checked.

3 0

3 years ago

Use the drop-down menus to complete each equation so the statement about its solution is true.

disa [49]

Answer:

Step-by-step explanation:

So,it would be easier to simplify the right equation, so when I say "the right equation", I mean the one I will make right now. It is 8x+9. So the first problem is 8x+9=x+?. Well, if there are no solutions, the slopes have to be the same, and the y-int doesn't matter. So the answer would be + 7x because that will make the x an 8x. If there is one solution, then the slope has to be different. So literally anything but 7x will work. Even constants. If there are infinitely many solutions, then the equations have to be the same. Meaning, you would have to add 7x and 9 to make the left equation the same as the right.

6 0

3 years ago