Answer:
Step-by-step explanation:
6x + 4y = 22
+
2x - y = 1
____________
8x + 3y = 23
27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.
The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)
To solve this problem you must apply the proccedure shown below:
1. You need to apply the Pythagorean Theorem:
Where <em>c</em> is the hypotenuse and the legs are<em> a</em> and <em>b.</em>
2. Now, you must substitute the values given in the problem above and solve for <em>b</em>:
Therefore, the answer is: The value of <em>b</em> is 6.92