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valina [46]
4 years ago
10

(r-1)^2 this is to the power of two

Mathematics
2 answers:
Levart [38]4 years ago
7 0
(r-1)^2= (r-1)(r-1)

Foil:

First: r*r=r^2
Outer: r*-1= -r
Inner: r*-1= -r
Last: -1*-1= 1

Put it together and simplify:
r^2-r-r+1
r^2-2r+1

Final answer: r^2-2r+1
mars1129 [50]4 years ago
6 0
<span>Use formula: (a-b)</span>² = a² - 2ab + b²<span>

(r-1)</span>² = r² - 2r + 1
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Jim provides photos for two online sites: site A and site B. Site A pays $0.85 for every photo Jim provides. The amount in dolla
yarga [219]
We can use the same equation to figure out with only substituting the amount he was paid per photo.

Site A    y = $0.85x      =  $0.85(5)  =  $4.25
Site B    y = $0.40x      =  $0.40(5)  =  $2.00

We can see that Jim was paid $2.25 more at site A than Site B.
6 0
3 years ago
Read 2 more answers
Latoya had a large collection of basketball cards. she gave half to her friend,Erin. And 1/4 to her brother. She now has 75 card
Kipish [7]

For this case, the first thing we must do is define variables.

We have then:

x: initial amount of cards

We now write the equation that models the problem:

x - (\frac{1}{2}) x - (\frac{1}{4}) x = 75

(\frac{1}{4}) x = 75\\x = 75 * 4\\x = 300

Therefore, the initial amount of cards is 300

Answer:

Latoya had 300 cards at the beginning

5 0
3 years ago
Read 2 more answers
If triangle ABC is similar to triangle DEC, find the values of x and y.
Mumz [18]

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal, it is obtained by Pythagoras theorem.

Step-by-step explanation:

The given are,

           From ΔABC,

                    AB= 6

                    BC= 10

                    AC = x

           From ΔDEC,

                    CD= 28

                    DE= 21

                    CE = y

Step:1

        Pythagoras theorem from  ΔABC,

                    BC^{2}=AB^{2} + AC^{2}...............(1)

       Substitute the values,

                   10^{2} = 6^{2} + AC^{2}

                  100 = 36 + AC^{2}

                   AC^{2} = 100 - 36

                           = 64

                    AC = \sqrt{64}

                    AC = 8

                  AC = x = 8

Step:2

        Pythagoras theorem for ΔDEC,

               CE^{2} = CD^{2}  + DE^{2}................(2)

       From the values,

              CE^{2} = 28^{2} + 21^{2}

             CE^{2} = 784 + 441

                     = 1225

              CE = \sqrt{1225}

              CE = 35

             CE = y = 35

Result:

         The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal.

5 0
3 years ago
In a place 100 soldiers had enough food for 60 days .how many soldiers leave the place so that food long last for 80 days
Tresset [83]

Answer:

48 soldiers leave the place.

Step-by-step explanation:

  • 100/60=80/x
  • 100x=4800
  • x=4800/100
  • x=48

hope it helps.

<h2>stay safe healthy and happy.</h2>
3 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
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