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3 years ago

(r-1)^2 this is to the power of two

2 answers:

7 0

(r-1)^2= (r-1)(r-1)

Foil:

First: r*r=r^2
Outer: r*-1= -r
Inner: r*-1= -r
Last: -1*-1= 1

Put it together and simplify:
r^2-r-r+1
r^2-2r+1

Final answer: r^2-2r+1

mars1129 [50]3 years ago

6 0

Use formula: (a-b)² = a² - 2ab + b²

(r-1)² = r² - 2r + 1

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A person noted that the angle of elevation to the top of a tree was 65 degrees at a distance of 11 feet from the tree. Using the

sashaice [31]

Answer:

approximate 23.590 feet

Step-by-step explanation:

tan 65° = x / 11 = 2.145

x = 11 x 2.145 = 23.595

5 0

2 years ago

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What is the approximate value of X? Round to the nearest tenth.

pychu [463]

Answer

Find out the value of x.

To prove

By using the trignometric identity

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

As given in the diagram.

$\theta = 50 ^{\circ}$

Perpendicular = x

Hypotenuse = 6

Put in the above identity

$sin\ 50^{\circ} = \frac{x}{6}$

$sin\ 50^{\circ} = 0.77\ (Approx)$

Put in the above

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Therefore Option (c) is correct .

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2 years ago

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On Tuesday Katy ran a mile in 8.34 minutes. She ran another mile in 7.89 minutes on Wednesday. What is the total time for both m

miv72 [106K]

She ran a total time of 16.23 minutes

3 0

2 years ago

Help!! Algebra help will give stars

Inessa [10]

Answer:

I'll answer one question

Step-by-step explanation:

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2 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

2 years ago