Can you guys pls help me with this

What is the sum of -7 and its additive inverse?

Virty [35]

Answer:

The sum of a number and its additive inverse is equal to 0.

Step-by-step explanation:

3 0

3 years ago

A worker on the production line is paid a base salary of $230.00 per week plus $0.78 for each unit produced. Write an equation

iogann1982 [59]

(a)

We are given

A worker on the production line is paid a base salary of $230.00 per week

so, base salary =230

Let's assume number pencils produced as x

plus $0.78 for each unit produced

now, we can find equation for earnings

$E(x)=230+0.78x$

now, we are given

her earnings of $446.84 for a week when she produced x units

so, we can set E(x)=446.84

and then we can solve for x

$446.84=230+0.78x$

$230\cdot \:100+0.78x\cdot \:100=446.84\cdot \:100$

$23000+78x=44684$

$23000+78x-23000=44684-23000$

$78x=21684$

$\frac{78x}{78}=\frac{21684}{78}$

$x=278$

so, number of pencils = 278........Answer

(b)

If the worker had produced twice that number of units

so, number of pencils =2*278=556

now, we can find earnings

$E(x)=230+0.78x$

now, we can plug x=556

$E(556)=230+0.78*556$

$E(556)=663.68$ .................Answer

3 0

3 years ago

PLEASE HELP 100 POINTS AND BRAINLY

gregori [183]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

3 years ago

Please help me solve this.

Vlada [557]

Answer:

<h2>I think that is a FORMULA.</h2>

it can't be solved if we don't know the values of atleast one of the x and y.

Hope this helps.

Good luck ✅.

8 0

2 years ago