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Reptile [31]
3 years ago
11

A box is 50 cm long. Which of these is closest to the length of this box in feet? (1 inch = 2.54 cm)

Mathematics
1 answer:
goblinko [34]3 years ago
3 0

First, convert cm to inches.

50/2.54 is roughly 19.69

There are 12 inches in a foot, so divide the 19.69 by 12.

19.69/12 is roughly 1.64

So the answer is C

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7 0
3 years ago
Hi help me please, I can't seem to figure this one out​
Nastasia [14]

Answer:

x= 2.73cm

<u>1cm : 0.6828 = 4cm : 2.73cm</u>

For the same angle we just work out 1cm first.

a^2+ b^2= c^2

0.82^2 + b^2 = 1^2 = changing to units 10

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Then x 3 and change units down by 10= 0.6828  

Step-by-step explanation:

Below shows why we must convert to mm from cm

a^2+ b^2= c^2

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0.2276 x 3 = 0.6828 cm

7 0
3 years ago
D is the wrong answer please help :(
Stella [2.4K]

This can be solved by Newton's binomial formula

Tk+1 = (n k) a∧(n-k) b∧k  k+1=7 => k=6, n=11 , a=-3x and b=-2y

T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6

T7= 462 (-3x)∧5 (-2y)∧6

The correct answer is A.

Good luck!!!


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