Answer:
-0.3*0.2*12, multiply -0.3 by 0.2 to get -0.06, now multiply 12 by it to get, -0.72.
Step-by-step explanation:
Answer:
Conclusion
Step-by-step explanation:
So you proved something Then you conclude something else)))
Answer:
15
Step-by-step explanation:
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
#SPJ1
