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xenn [34]
3 years ago
5

A rectangle has a length that is 4 ft more

Mathematics
2 answers:
Ludmilka [50]3 years ago
6 0

Answer:

length = 14 width = 10

Step-by-step explanation:

48/4=12

10+10+14+14=48

Mars2501 [29]3 years ago
4 0
Width = W = 10 ft

Length = L = 14 ft

P = perimeter = 48 ft

Explanation:


P rectangle = 2L+ 2W
L = W + 4
P = 48

Substitute into formula:
P rectangle = 2L + 2W
48 = 2( W + 4 ) + 2W
48 = 2W + 8 + 2 W
48= 4W + 8
48 - 8 = 4W
40 = 4W
W = 40/4 = 10
W = 10

The rectangle has a length that is 4 ft more than its width : L = W + 4

Substitute : L = 10 + 4 = 14
L = 14 ft

I hope this help!!!
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Find the distance between the points (<br> -<br> 10,12) and (15,12).
Nitella [24]
The distance formula is:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

We are given two points in the form (x,y), so plug in the values to the distance formula:

d= \sqrt{(-10-15)^2-(12-12)^2}

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

d= \sqrt{(-25)^2}

The square and square root cancel each other out leaving us with 25.

The answer is 25.


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3 years ago
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3 years ago
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vekshin1
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4 years ago
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X+3&lt;8 and 3(x+4)-11&lt;10
kondaur [170]

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

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3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

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4 0
4 years ago
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