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2 years ago

Christian walked directly south for 3.5

Mathematics

1 answer:

navik [9.2K]2 years ago

7 0

X is approximately equal to 5.7 miles

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What is the midpoint of the segment shown below

Softa [21]

Answer:

(-1, -1/2)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates and divide by 2

( -11+9)/2 = -2/2 = -1

To find the y coordinate of the midpoint, add the y coordinates and divide by 2

(0+-1)/2 = -1/2

(-1, -1/2)

6 0

2 years ago

There are 850 Douglas fir and Ponderosa pine trees in a section of forest bought by Karamazov Logging Co. The company paid an av

ki77a [65]

Answer:

350 Douglas fir, 500 Ponderosa pine

Step-by-step explanation:

Let f = the number of fir trees

and p = the number of pine trees.

Then, we have two conditions:

(1) f + p = 850

(2) 300f + 225p = 217 500

(3) p = 850 -f Subtracted f from each side of (1)

(4) 300f + 225(850 - f) = 217 500 Substituted (3) into (3)

300f + 191 250 - 225f = 217 500 Distributed 225

75f + 191 250 = 217 500 Distributed the 7

75f = 26 250 Subtracted 191 250 each side

(5) f = 350

350 + p = 850 Substituted (5) into (1)

p = 500 Subtracted 350 from each side

The company bought 350 fir trees and 500 pine trees.

Check:

(1) 350 + 500 = 850 (2) 300 × 350 + 225 × 500 = 217 500

850 = 850 105 000 + 112 500 = 217 500

217 500 = 217 500

OK.

8 0

2 years ago

Grace can read 840 words in 7 minutes. At that rate, how many words can she read in one hour

slega [8]

Answer:

5740

Step-by-step explanation:

7 0

2 years ago

PLEASE HELP I GIVE BRAINLIEST

Galina-37 [17]

I Think it would either be D or C

(I’m not sure, let me know if I’m wrong)

4 0

2 years ago

The area of a circular oil slick on the surface of the sea is increasing at a rate of [150m^2/s] how fast is the radius changing

Akimi4 [234]

Answer with Step-by-step explanation:

We are given that

$\frac{dA}{dt}=150m^2/s$

a.Radius =25 m

We have to find rate of change of radius.

We know that

Area of circle, $A=\pi r^2$

Differentiate w.r.t time

$\frac{dA}{dt}=2\pi r\frac{dr}{dt}$

Substitute the values then we get

$150=2\pi (25)\frac{dr}{dt}$

$\frac{dr}{dt}=\frac{150}{50\pi}=\frac{3}{\pi} m/s$

$\frac{dr}{dt}=\frac{3}{\pi} m/s$

b.A= $1000m^2$

Substitute the values then we get

$1000=\pi r^2$

$\pi=3.14$

$r^2=\frac{1000}{3.14}$

$r=\sqrt{\frac{1000}{3.14}}=17.8m$

$\frac{dA}{dr}=2\pi r\frac{dr}{dt}$

Substitute the values then we get

$150=2\pi(17.8)\frac{dr}{dt}$

$\frac{dr}{dt}=\frac{150}{2\pi(17.8)}=\frac{150}{35.6\pi}$ m/s

$\frac{dr}{dt}=\frac{75}{17.8\pi}$ m/s

4 0

2 years ago