Question

Please answer and work it out and round to the nearest tenth. Thank you!

Answer 1

The length of UV is 6 in because it is parallel to WX.

Find the length of TV:

$TV^{2} =\sqrt{TU^{2} +TV^{2}}$

$TV^{2} =\sqrt{12^{2} +6^{2}}$

$TV^{2} =\sqrt{144+36}$

$TV^{2} =\sqrt{180}$

$TV =6\sqrt{5} = 13.41640786$

The length of VX is 9 in because it is parallel to UW.

$TX^{2} =\sqrt{TV^{2} +VX^{2}}$

$TX^{2} =\sqrt{180 +9^{2}}$

$TX^{2} =\sqrt{180 +81}$

$TX^{2} =\sqrt{261}$

$TX =16.15549442$

TX = 16.2 inches

Answer 2

Answer:

The value of TX is 15 in

Step-by-step explanation:

According to Pythagoren theorem

Hyp² = Base² + Perp²

Putting the values

Hyp² = 12² + 9²

Hyp²  = 144 + 81

Hyp² = 225

taking square root on both sides

Hyp = 15