Answer:
The squirrel maximum height (h) = 21.125 ft
Step-by-step explanation:
The objective of this question is to determine the squirrel's maximum height.
Given that:
h = -2t² + 9t + 11
Differentiating h with respect to t, we get;
At the time dh/dt = 0, the velocity is maximum
Thus;
-4t = -9
4t = 9
t = 9/4
t = 2.25 seconds
From;
h = -2t² + 9t + 11
h = - 2(2.25)² + 9(2.25) + 11
h = - 10.125 + 20.25 + 11
h = 21.125 ft
Answer:
1. B
2. D
3. B
4. D
5. C
6. A
7. What is the estimated sum of "?" what are we estimating?
8. C
9. C
10. B
Step-by-step explanation:
1st question
1/4 ≤ 8/19 ≤ 3/4, so round it to 1/2.
1/4 ≤ 6/13 ≤ 3/4, so round it to 1/2.
Estimating:
1/2 + 1/2 = 1
2nd question
220 9/11 divided by 6 19/20 = 2.99542184434
Rounded/estimated = 3
3rd Question
Estimate 8 1/8 (common sense)
8 1/8 = 8.
4th Question
Assuming cups = 2.
2x24 = 48.
5th Question
3
6th Question
Add and estimate
7th question
What is the estimated sum of "?" what are we estimating?
8th question
6/7 > 3/4, so round it to 1.
1/4 ≤ 4/7 ≤ 3/4, so round it to 1/2.
Estimating:
1 + 1/2 = 1 1/2
9th Question
Round 7 to 8. It is over half, so it would be 8, which = 1
10th Question
Half of 20 = 10, 9 isn't above 10.
So round backwards to 24.
Hello!
The Pythagorean Theorem is a²+b²=c², where a and b are the legs are a and b, and the hypotenuse is c. Since we already have the hypotenuse we will subtract the squares to find a.
100-64=36
√36=6
The length of the other leg is 6 feet.
I hope this helps!
1 = 6 out of 15
2 = 4 out of 15
3 = 5 out of 15
4 = 11 out of 15
hope this helps you