A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1690 feet, what are the dimensions o
f the field?
The width of the field is __ feet.
The length of the field is __ feet.
The width of the field is __ feet.
The length of the field is __ feet.
1 answer:
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ANSWER:
0.25
i attached my work, hope this helps
0.25
i attached my work, hope this helps
The only that has the shape of the one below.
y = -4(x^3 + 7x^2+8x - 16)
Let x = 1
y = - 4(1 + 7 + 8 - 16)
y = 0
y = -4(x -1)(x^2 + 8x + 16)
y = -4(x - 1)(x + 4)^2
y = -4(x^3 + 7x^2+8x - 16)
Let x = 1
y = - 4(1 + 7 + 8 - 16)
y = 0
y = -4(x -1)(x^2 + 8x + 16)
y = -4(x - 1)(x + 4)^2