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3 years ago

How would I solve this?(3x-4) - (4x-1)

Mathematics

1 answer:

saveliy_v [14]3 years ago

4 0

Answer:

-x - 3

Step-by-step explanation:

(3x - 4) - (4x - 1) =

The first set of parentheses is unnecessary, so you can just remove it.

= 3x - 4 - (4x - 1)

To remove the second set of parentheses, you must distribute the negative sign to its left by the terms inside the parentheses. To do this, change every sign inside the parentheses.

= 3x - 4 - 4x + 1

Now combine like terms. Terms with x are like terms and are combined together. Therms without x are like terms and are combined together.

= 3x - 4x - 4 + 1

= -x - 3

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The diameter of a circle is 6 m. Find its area in terms of pi

Pie

<h2>Answer:</h2><h2>9 pi m^2</h2>

Solution,

Diameter=6 m

Radius= 6/2=3m

Area of circle= pi r ^2

 = pi *(3)^2

 =9 pi metre^2

Hope it helps

Good luck on your assignment

7 0

3 years ago

Read 2 more answers

A middle school campus is shaped like a rectangle with a width of 1/4 mile and a length of 1/2 mile. A map of the campus has a w

igomit [66]

Answer:

A) 1:4

Step-by-step explanation:

#We first calculate the campus' area:

$a=lw\\\\=\frac{1}{4}\times \frac{1}{2}\\=0.125 \ mi^2$

#We then calculate the campus' map area in square ft:

$A=lw\\\\=0.5 \times 1\\\\=0.5 ft^2$

Ratio is a comparison between two dimensions:

$Ratio=\frac{0.125}{0.5}\\\\=0.25\\\\=\frac{1}{4}\\\\=1:4$

Hence, the ratio of the area in square miles of the campus to the area in square feet of the map is 1:4

3 0

3 years ago

How do you right 2.1 in words

Lelu [443]

Answer: Two and one tenth.

5 0

3 years ago

I need help please as soon as possible with both :(

Over [174]

Answer:

X=0

(8,7)

Step-by-step explanation:

8 0

3 years ago

(5+2 i)(4-3i) - (5-2yi)(4-3i) in a + bi form, where y is a real number.

ElenaW [278]

(5+2 i)(4-3i) - (5-2yi)(4-3i)

Factorize out (4 -3i)

(4 -3i)( (5 +2i) - (5 -2yi) )

= (4 -3i)(5 +2i - 5 + 2yi)

= (4 -3i)(5 - 5 + 2i + 2yi)

= (4 -3i)(2i + 2yi)

= (4 - 3i)(2 + 2y)i. Let's multiply the first two.

(4 - 3i)(2 + 2y) = 2*(4 -3i) + 2y*(4 - 3i)
 = 8 - 6i + 8y - 6yi
 = 8 + 8y - 6i - 6yi

(4 - 3i)(2 + 2y)i = (8 + 8y - 6i - 6yi)i Note: i² = -1
 = 8i + 8yi - 6i² - 6yi²
 = 8i + 8yi - 6(-1) - 6y(-1)
 = 8i + 8yi + 6 + 6y
 = 6 + 6y + 8i + 8yi
 = (6 + 6y) + (8 + 8y)i In the form a + bi

5 0

3 years ago

How would I solve this?(3x-4) - (4x-1)​

How would I solve this?(3x-4) - (4x-1)