It is true. This is because, if you keep on adding acid in a solution with OH⁻ ion, H⁺ ions keeps on neutralizing OH⁻ ions.
Answer:
Explanation:
Your phone is not good for you. Maybe listen to your teacher. There’s no more online classes honey.
Answer:
Explanation:
IONIC-
metal & nonmental
1st word doesn't start with "mono"
2nd word can end in "-ate or -ite" (Polyatomic ions)
May need roman numerals
Reduce charges when writing formula
COVALENT-
2 non-metals
Names uses prefixes
2nd word can end in - ide
BOTH-
2nd element is a non-metal
Answer:
<h2>50 kg.m/s</h2>
Explanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 10 × 5
We have the final answer as
<h3>50 kg.m/s</h3>
Hope this helps you
Answer:
397 L
Explanation:
Recall the ideal gas law:
![\displaystyle PV = nRT](https://tex.z-dn.net/?f=%5Cdisplaystyle%20PV%20%3D%20nRT)
If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:
![\displaystyle \frac{P}{RT} = \frac{n}{V}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BP%7D%7BRT%7D%20%3D%20%5Cfrac%7Bn%7D%7BV%7D)
The left-hand side is simply some constant. Hence, we can write that:
![\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bn_1%7D%7BV_1%7D%20%3D%20%5Cfrac%7Bn_2%7D%7BV_2%7D)
Substitute in known values:
![\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})} = \frac{(13.15\text{ mol })}{V_2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%283.31%20%5Ctext%7B%20mol%7D%29%7D%7B%28100%20%5Ctext%7B%20L%7D%29%7D%20%20%3D%20%5Cfrac%7B%2813.15%5Ctext%7B%20mol%20%7D%29%7D%7BV_2%7D)
Solving for <em>V</em>₂ yields:
![\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V_2%20%3D%20%5Cfrac%7B%28100%20%5Ctext%7B%20L%7D%29%2813.15%29%7D%7B3.31%7D%20%3D%20397%20%5Ctext%7B%20L%7D)
In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.
(Assuming 100 L has three significant figures.)