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3 years ago

The total number of atoms represented by the formula Fe3(PO4)2 is

Chemistry

2 answers:

In-s [12.5K]3 years ago

8 0

C is the answer 3 + 2 +8 = 13

horsena [70]3 years ago

7 0

Answer:

Explanation:

We have to keep in mind for this question that we have to take into account the subscripts.

$Fe_3(PO_4)_2$

The subscript will affect only the number in the left, so the first part would be:

$Fe_3$

In this part we will have 3 iron atoms. Then we will have:

$(PO_4)_2$

In the $PO_4$ we will have 1 atom of P and 4 atoms of O. (When we dont have any number as subscript we have to assume that we have a "1")

Then we have a "2" out side the the parenthesis $(PO_4)_2$ , so we have to multiply by "2" all the atoms inside the parenthesis, so:

1 atom of P x 2 = 2

4 atoms of O x 2 = 8

So, in total we will have:

3 atoms of Fe + 8 atoms of O + 2 atoms of P = 13 atoms

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3 years ago

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3 years ago

In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so

gulaghasi [49]

Answer: The moles of hydroxide ions present in the sample is 0.0008 moles

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL$

Putting values in above equation, we get:

$1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M$

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

$0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol$

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0

3 years ago

How many total atoms are in 0.380 g of P2O5

pogonyaev

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7 0

3 years ago