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3 years ago

The total number of atoms represented by the formula Fe3(PO4)2 is

Chemistry

2 answers:

In-s [12.5K]3 years ago

8 0

C is the answer 3 + 2 +8 = 13

horsena [70]3 years ago

7 0

Answer:

Explanation:

We have to keep in mind for this question that we have to take into account the subscripts.

$Fe_3(PO_4)_2$

The subscript will affect only the number in the left, so the first part would be:

$Fe_3$

In this part we will have 3 iron atoms. Then we will have:

$(PO_4)_2$

In the $PO_4$ we will have 1 atom of P and 4 atoms of O. (When we dont have any number as subscript we have to assume that we have a "1")

Then we have a "2" out side the the parenthesis $(PO_4)_2$ , so we have to multiply by "2" all the atoms inside the parenthesis, so:

1 atom of P x 2 = 2

4 atoms of O x 2 = 8

So, in total we will have:

3 atoms of Fe + 8 atoms of O + 2 atoms of P = 13 atoms

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3 years ago

If 550 mL of a 3.50 M KCl solution are set aside and allowed to evaporate until the volume of the solution is 275 mL, what will

tatiyna

Answer:

Explanation:

Molarity = number of moles / volume

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2 years ago

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A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h

frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

$Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]$

Where;

$\frac{f_2}{f_1}$ is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

$Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1} = 10^{0.7289}\\\\\frac{f_2}{f_1} = 5.356$