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Yuliya22 [10]
2 years ago
8

Plss solve 29 for me.with the steps plsssßs I am begging u

Mathematics
1 answer:
lakkis [162]2 years ago
5 0
That means that the first rectangle and the first triangle ave athe same perimiter

so therefor
perimiter=sides added up
 rectangle has 4 sides bu 2 is given so double it since the other side is same legnth
rec=x+x+4
multiply 2
2x+2x+8=4x+8=perimiter
this is equal to perimiter of triangle which is
x+9+x+5+x=3x+14
therefor
4x+8=3x+14
subtract 3x from both sides
x+8=14
subtract 8 from both sides
x=6
first one x=6





second rectangle and second triangle
s+7 and 3s
2 sides
2s+14+6s=p
8s+14=p

traignel=2s+12+2s+12+2s+12=6s+36=p
they are equal so
8s+14=6s+36
subtract 6s from both sides
2s+14=36
subtract 14 from both sides
2s=22
divide both sideds by 2
s=11






the values are
pair one:
x=6

pair 2:
s=11

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3 years ago
GEOMETRY. PLEASE HELP. I'M STUMPED!!!
tatiyna
Given the triangles ABC and PQR.
Angle A = Angle P
Angle B = Angle Q
Angle C = Angle R

Angle B = 3v+4
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