L=w+2 and 2w+2l=44
substitute equation for length in perimeter equation
2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10
substitute width into length equation to get length
l=10+2
l=12
a=lw
a=12*10
a=120 cm^2
^ You again? Quit being sus and answer the question here instead of elsewhere.
To find the mean, all you have to do is add each number and then divide by how many numbers you added.
So, 38 + 29 + 16 + 42 + 33 = 158. There were five numbers added, so the next step is to divide 158 by 5. That equals 31.6 as your answer.
Do you mean add are subtract
i will glad to help in comments
if you awnser
Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
<u>Step-by-step explanation:</u>
As given by the statement in the problem,
Q may be the middle point, which cut the diagonal PA into 2 equal halves.
In rhombus, diagonals meet at right angles.
which means that PQ = QA
x+2 = 3x - 14
Grouping the terms, we will get,
3x -x = 14+ 2
2x = 16
dividing by 2 on both sides, we will get,
x = 16/2 = 8
8+2 = 3(8) - 14 = 10 = PQ or QA
16.2 miles.
Since she paid a $5 tip, the cost for her fare was $23.50. Let x be the number of 0.2-mile increments in the trip:
23.50 = 2.50 + 1 + 0.25(x-1)
This equation comes from the 2.50 home pick-up fee; $1 for the first 0.2-mile increment; and 0.25 for each other 0.2-mile increment.
Using the distributive property, we have:
23.50 = 2.50 + 1 + 0.25*x - 0.25*1
23.50 = 2.50 + 1 + 0.25x - 0.25
Combining like terms,
23.50 = 0.25x + 2.75
Subtracting 2.75 from both sides, we have:
23.50 - 2.75 = 0.25x + 2.75 - 2.75
20.25 = 0.25x
Dividing both sides by 0.25, we have:
20.25/0.25 = 0.25x/0.25
81 = x
This means there are 81 0.2-mile increments in her trip. 81(0.2) = 16.2 miles
