That is a one hundred thousand number. To round it you need to know this: 5 or more make it go up (make it the next number. For example: 19,530. It would be rounded to 20,000 because of the 5) 4 or less let it be (EXAMPLE : 8,213. It would be 8,000. Because of the 4.)
Then you need to find the ten thousand. In this case it is the 0. (104,229) Then you round it off to 100,000. The answer is 100,000.
Answer: 11.05
Step-by-step explanation:
Divide 5.20 by 8 to find the price of each bag (which is .65 cents.) Multiple .65 by 20 (13). 15% of 13 is 1.95. 13 - 1.95 is 11.05
PS: 1.95 is the discount. Hope this helps. Have a good day.
Answer:
![1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}](https://tex.z-dn.net/?f=1.%20%5Cquad%5Cdfrac%7B1%7D%7Bk%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%5C%5C%5C%5C2.%20%5Cquad%5Csqrt%5B7%5D%7Bx%5E5%7D%5C%5C%5C%5C3.%20%5Cquad%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7By%5E2%7D%7D)
Step-by-step explanation:
The applicable rule is ...
![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
It works both ways, going from radicals to frational exponents and vice versa.
The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.
Answer:
Average speed of the particle is 13 miles per hour.
Step-by-step explanation:
From the given question expression for distance traveled by the particle is

Then fro the time interval (1, 4) we have to calculate the average speed.
At t=1, s=2(1)²+3(1) =2+3 =5 miles
And at t = 4 s=2(4)²+3(4) = 2(16)+12 = 32+12 =44 miles
So displacement of the particle in the time span from 1 to hours.
s = (44-5) = 39 miles
And the times taken = (4-1) =3 hours
From the formula speed = displacement/(time taken for displacement)
V = 39/3 = 13 miles/hour