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MAVERICK [17]
3 years ago
5

every evening jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she

had 40 coins, all of them dimes and quarters. when she added them up, she had a total of $7.75. how many dimes did jenna have
Mathematics
1 answer:
Darya [45]3 years ago
8 0
Let Q= the number of quarters and D= the number of dimes.
Q+D= 40 coins
0.25Q+0.1D= $7.75
Rewrite equation 1 as: D = 40-Q and substitute into equation 2
0.25Q+0.1(40-Q)= 7.75 Simplify the left side
0.25Q+4-0.1Q= 7.75 Subtract 4 from both sides
0.25Q-0.1Q= 3.75 Convime like terms on left side
0.15Q= 7.75 Divide both sides by 0.15
Q=25 and D= 40-Q
D= 40-25 which is 15
So Jenna had 25 quarters and 15 dimes.
<span>To check multiply 25 x 25 and 15x10 which equals 625 and 150 this equals 775 so this is 7.75</span>
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Can someone help me? I figured out part B however, I am struggling with part A and I would be so happy if any of you helped me.
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<h3>Answer:  262,785</h3>

Note: you may need to delete the comma

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The info "5 months" is never used to compute the mean. We could easily replace it with "6 months" or "7 months" or any stretch of time, and still get the same answer. So we'll ignore this value.

What we'll do is add up the 21 items given to us, and then divide by 21.

Because there are so many values, and it's easy to get lost, I'm going to add up across the rows

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That value then rounds up to 262,785

If your teacher just wanted things to the nearest whole number (without rounding up), then the answer would be 262,784

Side note: using a spreadsheet program would probably be the most efficient/fastest method for this type of problem.

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