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docker41 [41]
3 years ago
8

Find two supplementary angels such that the measure of the first angle is 38° less than three times the measure of the second

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0


angle 1+ angle 2=180    supplementary angles add up to 180

angle 2=x     assign angle a variable

angle 1= 3x-38      find equation for first angle

3x+x-38=180      set both angles added together equal to 180

4x-38=180        combine like terms

4x=218        add 38 to both sides

x=54.5        divide by 4

angle 2= 54.5

angle 2= (3x54.5)-38   plug back in and solve

angle 1= 125.5           


solmaris [256]3 years ago
7 0
3x-38
x-2nd angle

3x-38+x=180
4x-38=180
4x=218
x=54.5

First angle 
3(54.5)-38
163.5-38
125.5
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2 years ago
Which comparison statement is true? A. 7.24 &lt; 7.240 B. 7.24 &gt; 7.240 C. 7.24 = 7.240
KIM [24]
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8 0
2 years ago
Read 2 more answers
How do I factor x^4-5x^2+6?
Vilka [71]

Answer:

=(x^2-3)(x^2-2)

Step-by-step explanation:

So we have the expression:

x^4-5x^2+6

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

=u^2-5u+6

This is a technique called quadratic u-substitution. Now, we can factor in this form.

We can use the numbers -3 and -2. So:

=u^2-2u-3u+6

For the first two terms, factor out a u.

For the last two terms, factor out a -3. So:

=u(u-2)-3(u-2)

Grouping:

=(u-3)(u-2)

Now, substitute back the x² for u:

=(x^2-3)(x^2-2)

And this is the simplest form.

And we're done!

3 0
2 years ago
I need help ,, i don't understand !<br>​
otez555 [7]

Answer: B

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7 0
2 years ago
I am having trouble with this problem. I need to find the lengths of this right triangle. How would you do this?
podryga [215]
You labeled the triangle wrong sides 'a' and 'b' are supposed to be the sides that make the right angle.  the other side is called the hypotenuse which is the longest side which you should have labeled 'c'

so Pythagorean theorem says
a^2+b^2=c^2
so
(2x+1)^2+(11x+5)^2=(12x+1)^2
distribute
(4x^2+4x+1)+(121x^2+110x+25)=(144x^2+24x+1)
add like terms
125x^2+114x+26=144x^2+24x+1
subtract 125x^2 from both sides
114x+26=19x^2+24x+1
subtract 114x from both sides
26=19x^2-90x+1
subtract 26 from both sides
0=19x^2-90-25
factor
(x-5)(19x+5)=0
therefor x-5=0 and/or 19x+5=0
so
x-5=0 add 5 to both sides
x=5
19x+5=0
subtract 5 from both sides
19x=-5
divide both sides by 19
x=-5/19
since side legnths can't be negative, we can cross this solution out

so x=5
subtitute
1+2x
1+2(5)
1+10=11
side a=11

11x+5
11(5)+5
55+5=60
side b=60

12x+1
12(5)+1
60+1=60
side c=61
add them all up
side a+b+c=11+60+61=132=total legnth
5 0
2 years ago
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