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Mumz [18]
4 years ago
6

Can someone please help me?

Mathematics
1 answer:
professor190 [17]4 years ago
8 0

Answer:

correct 34324234324324

Step-by-step explanation:

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(Choice A)
Tasya [4]

Answer:

That is an obtuse scalene triangle

Step-by-step explanation:

Scalene- has no congruent sides

Obtuse - has an angle that is greater than 90

we can use Pythagorean theorem to confirm this

The Pythagorean theorem states that in an obtuse triangle the hypotenuse squared is greater than the two legs squared added together

so basically 7^2>4^2+5^2\\7^2=49\\4^2=25\\5^2=25\\25+16=41\\49>41

therefore it is an obtuse scalene

3 0
3 years ago
Read 2 more answers
Look at picture for question
lawyer [7]
2 1/3 cups of pizza sauce will make the pizza
7 0
3 years ago
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I promise Brainliest to the first to answerBased on the graph below, what is ƒ(3)? Each tick represents 1 unit.
Zigmanuir [339]

Answer:

So first we need to find 3 on the x position. Any time you have a number passed into a function it means we need to get the x coordinate. Then we trace the point on the line which has 3 as a coordinate for x. Then the output will give us the y coordinate. So we can see that for 3 the y on the line is 3 also. Therefore the answer is

<h2><u>3</u></h2>

4 0
3 years ago
What is measure of angle R?
saul85 [17]
Check the picture below.

if you need the angle in Degrees, make sure your calculator is in Degree mode.

8 0
4 years ago
Read 2 more answers
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

8 0
4 years ago
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