The answer is the letter B
Answer:
B'(-7 , -2)
Step-by-step explanation:
First we must understand the coordinate-axis, when we want to move a point to the left or right we do it on the x-axis. to move up or down is on the y axis.
now if we move to the left we go to the negative and to the right the positive
as we are going to move to the left we have to subtract the value that he gave us (4) only to the part of x
B(-3 , -2)
-3 - 4 = -7
B'( -7 , -2)
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer: y =13 because y represents how the number of how many times you multiply 2/3 to get to 14/39 so you divide 39 by 3 and get 13. now if you times 2 by 13, you don't get fourteen so I'm confused on that part and I might be wrong so I'm sorry if I'm wrong
Answer:
<em><u>4(10+9) - 40 + 36</u></em>
<em><u>9(5+2) - 45 + 18</u></em>
<em><u>3(12+7) - 36 + 21</u></em>
