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3 years ago

What are three numbers between 4.1 4.2? please help

Mathematics

1 answer:

Andrew [12]3 years ago

3 0

4.11
4.111
4.12
4.13
4.17
4.19
anything like this

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PLEASE HELP ASAP! :( Please help me find a, b, c, d!

s2008m [1.1K]

Answer:6 3 7 8 abcd and that order

Step-by-step explanation:

7 0

2 years ago

Plz help me. Jose travels 34 miles from home to work on a daily basis. If she takes up a job that is 1 and 1/2 times as far as h

algol13

Answer:

I think it is either 85 or 51 because the question was not specific

Step-by-step explanation:

I am not entirely sure if you mean Jose changed jobs or added a new job on top but i will do both.

34/2=17

17+34=51

51+34=85

5 0

2 years ago

Read 2 more answers

What is the value of x? sin41°=cos x Enter your answer in the box. x = °

creativ13 [48]

Answer:

x = 49°

Step-by-step explanation:

The sine of an angle is equal to the cosine of its complement:

x = 90° -41° = 49°

5 0

3 years ago

Plz help urgent !!!! will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...