Answer:
Poster’s perimeter = 150 in
Step-by-step explanation:
Given:
Width of poster = 2.5 ft = 2.5 × 12 = 30 in
Find:
Poster’s perimeter.
Computation:
Height of poster = [30×6]/4
Height of poster = 45 in
Poster’s perimeter = 2 [Width of poster + Height of poster]
Poster’s perimeter = 2 [30+45]
Poster’s perimeter = 2 [75]
Poster’s perimeter = 150 in
Answer: x=-1
Step-by-step explanation:
−10+x+4−5=7x−5
−10+x+4+−5=7x+−5
(x)+(−10+4+−5)=7x−5(Combine Like Terms)
x+−11=7x−5
x−11=7x−5
Step 2: Subtract 7x from both sides.
x−11−7x=7x−5−7x
−6x−11=−5
Step 3: Add 11 to both sides.
−6x−11+11=−5+11
−6x=6
Step 4: Divide both sides by -6.
−6x
−6
=
6
−6
x=−1
Answer:
-3
Step-by-step explanation:
The length of a segment is
sqrt( ( y2-y1)^2 + (x2-x1) ^2) = 2 sqrt(10)
sqrt( ( a-4 - -1)^2 + (2a -4) ^2) = 2 sqrt(10)
sqrt( ( a-4 +1)^2 + (2a -4) ^2) = 2 sqrt(10)
Combine like terms
sqrt( ( a-3)^2 + (2a -4) ^2) = 2 sqrt(10)
Square each side
( a-3)^2 + (2a -4) ^2) = 4 *(10)
FOIL the left side
a^2 -6a +9 + 4a^2 -16a +16 = 40
Combine like terms
5a^2 -22a +25 = 40
Subtract 40 from each side
5a^2 -22a -15 =0
Factor
(a - 5) (5 a + 3) = 0
Using the zero product property
a-5 =0 5a +3 = 0
a = 5 5a = -3
a=5 a = -3/5
The product of the terms is
5 * -3/5 = -3
Answer:
There are 40 musicians that are only marching band.
Step-by-step explanation:
Since we knot that there are 25 musicians that do both that means there is 60 - 25 = 35 musicians who do only jazz band. From his we can answer the question because....
100 = a + b + c
Where "a" is the number of musicians who go only to jazz, "b" is the number of people who do both, and "c" is the number of people that go only to the marching band. From here we can do this....
100 = a + b + c
c = 100 - a - b
Substitute the value we found outa and get.....
c = 100 - 35 - 25
c = 40
The answer is -8
====================================================
Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
-----------------------
The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
