Answer:
3 × 5 × 5 × 2 × 2 × 2
Step-by-step explanation:
Make a factor tree.
But let me explain the above to prove it's correct.
3 × 5 = 15
15 × 5 = 75
75 × 2 = 150
150 × 2 = 300
300 × 2 = 600
Therefore 600 as a product of prime factors is: <u>3 × 5 × 5 × 2 × 2 × 2</u>
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
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Step-by-step explanation:
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Answer:
150 ft
Step-by-step explanation:
