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Nutka1998 [239]
3 years ago
7

What is 3(x + 1) = -2 (x - 1) + 6

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

Answer:

x=2/5

Step-by-step explanation:


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14-2(x+8)=5x-(3x-34)
Scilla [17]

Answer:30=-34


Step-by-step explanation:

First you distribute so 2×X is 2X

2×8 is 16 then you do the other side but you put a one in front of the- so it goes 1 times 3x is 3x and you turn the minus into a plus sign and turn the positive 34 into a negative 34 so -34× 1 is -34 then write that out to look like 14-2X+16= 5X -3X + -34 then you add or subtract the commons which is 14+16= 30 and 5X-3X=2X so now your equation is 30-2x=2X+(-34) then you want to get your X on the same side so you subtract 2X from the right side and the left side then your left 30=-34

4 0
3 years ago
There are 34 balls in a bucket. The balls are numbered from 1 to 34. One ball is randomly selected from the bucket. What is the
V125BC [204]

Answer:

1/34

Step-by-step explanation:

There is one 13 ball and there are 34 balls total.

1/34 is the answer. :)

4 0
3 years ago
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Please answer quick!
tatuchka [14]
4 * (25 * 1.2) = (4 * 25) * 1.2
3 0
3 years ago
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Combina los términos semejantes<br> -16 + 8x +20x -5y
mrs_skeptik [129]
28x+-21 you simplify them first
7 0
3 years ago
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
3 years ago
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