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lesantik [10]
3 years ago
5

Can I please have help with numbers 28 and 30 and can you check if I got number 29 correct? THANK YOU

Mathematics
1 answer:
sweet [91]3 years ago
6 0
28 is B 
30 is C and 
29 is correct as it is!
Hope this helps.
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Write an equation in slope intercept form that describes a line with a slope of 3 and containing the point (5,-1)
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Answer:

<h2>         y = 3x - 16</h2>

Step-by-step explanation:

Equation of line with a given slope of a and containing a given point (x₀, y₀):

y - y₀ = a(x - x₀)

a = 3,  x₀ = 5,  y₀ = -1

So:

y - (-1) = 3(x - 5)  

y = 3x - 15 - 1

<u>y = 3x - 16</u>

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3 years ago
etta bought a calculator for $15. Glenn found the same model for $9.79. How much more did Etta pay than Glenn
ololo11 [35]

5.21.

To find this, give both numbers decimal points before setting up a subtraction equation as so:

15.00 - 9.79

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3 years ago
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Solve for x and explain how you got your answer <br> 3x + 4 = 16
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Answer:

X = 4

Step-by-step explanation:

3x=16-4

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X=12/3

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3 years ago
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

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The shipment is 5 5/7 tons
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