5 + 6a + 11b
terms: 5; 6a; 11b
Factors of 5: 1; 5
Factors of 6a: 1; 2; 3; 6; a; 2a; 3a; 6a
Factors of 11b: 1; 11; b; 11b
Answer:-21
Step-by-step explanation:
3•(-7)
3 x -7=-21
Answer:
D,0,2,-2
Step-by-step explanation:
2x^5-3x^3-20x=0
x(2x^4-3x^2-20)=0
x=0
or 2x^4-3x^2-20=0
put x²=t
2t²-3t-20=0
-20×2=-40
8-5=3
8×-5=-40
2t²-(8-5)t-20=0
2t²-8t+5t-20=0
2t(t-4)+5(t-4)=0
(t-4)(2t+5)=0
t=4
x²=4
x=2,-2
t=-5/2
x²=-5/2
it gives imaginary root. so real rational roots are 0,2,-2
