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spayn [35]
3 years ago
7

(3h-2m)(2h+m) multiple

Mathematics
1 answer:
den301095 [7]3 years ago
4 0
If you want to multiply 2 binomials, take each term in the first set of parentheses and multiply it to every term in the second set of parentheses:
3h*(2h+m) = 3h^2+3hm
-2m*(2h+m) = -4hm-2m^2
Combine like terms: (3hm-4hm)
3h^2-hm-2m^2
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I will do the first one only. The second question is done the same way.

Replace every x you see in the function with 2b and do the math.

f(x) = x^2 + 2x + 1

Let x = 2b

f(2b) = (2b)^2 + 2(2b) + 1

f(2b) = 4b^2 + 4b + 1

Did you follow? That's all there is to it.





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