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SVEN [57.7K]
3 years ago
11

Which graph is represents the function f(x)=3x-2/x-2

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

I believe its graph D. Though you haven't showed any graphs, please check out the link below, I don't wanna take credit for copy and pasting anyone's work.

Step-by-step explanation:

This guys super smart too, trust. <3

brainly.com/question/9305138

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What is 1/3 of 18<br> Fraction problems
polet [3.4K]
The answer is six. All you have to do is divide 18 by 3.
4 0
3 years ago
Read 2 more answers
Heidi earns 3% commission on jewelry she sells each week last week she sold 5,000 worth of jewelry how much did she make in comm
Alex17521 [72]
3% commission of 5000 = $150
6 0
3 years ago
24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Nostrana [21]
Red:green

5:3
5+3=8
8 units
4qt=8 units
divide by 8
0.5qt=1unit
5 unit=red
5*0.5=2.5qt, red=2.5qt
3unit=lime
0.5*3=1.5qt
1.5qt, 2/3 of that is yellow, 1/3 is blue, 1.5 times 2/3=1, 1.5 times 1/3=0.5
result:
2.5qt red
1qt yellow
0.5qt blue

6 0
3 years ago
The number of daily sales of a product was found to be given by S = 600xe−x2 + 600 x days after the start of an advertising camp
Elena-2011 [213]

Answer:

a. 20520

b. 12600

Step-by-step explanation:

Given the function S = 600xe^-x² + 600.

a. To find the average, we have to find the definite integral of the function because average, as it is known, is the sum of data points divided by the size of its dataset, this can be used for discrete data. Integral formula is just the continuous form of average, so we are using integral because we were given an interval of x= 0 to X = 30.

Let's integrate 100xe^x² first. Let –x² = u, this means –2xdx = du and we have dx = –du/2x. Also, when x = 0, u = –(0)² = –0 and when x = 30, u = –(30)² = –900. When we make our substitutions we have:

–600(xe^udu)/2x = –600(e^udu)/2 upon integrating that we have –600(e^u)/2. Applying our interval we have

–600[(e^900)/2 – (e^0)/2] ≈ – [– 3.7 – (1/2)] = –600 (–4.2) = 600 x 4.2 = 2520

Now let's integrate 600, with the interval x = 0 to x = 30 (we are using this interval here because the substitution we made didn't affect this).

We have, upon integrating:

600x.

Substituting our intervals we have:

600(30 – 0) = 600 x 30 = 18000.

Adding that up we have: 2520 + 18000 = 20520.

b. The same method is needed, just difference of interval.

Therefore, after integrating the first component with intervals u = 900 to u = 2500 (from x² = u) we have:

–600[(e^2500)/2 – (e^900)/2] ≈ –600[2.7 – 3.7] = –600(–1) = 600.

Then for the second component:

600x using x = 30 to x = 50

600(50 – 30) = 600 x 20 = 12000.

Adding that up we have:

12000 + 600 = 12600.

4 0
3 years ago
Consider the numbers 3/10 and 4/13
serg [7]
Make bototm number same
3/10 times 13/13=39/130
4/13 times 10/10=40/130

A.
39/130 and 40/130
they are 1/130 apart


B.
a ratioal number between
39/130=390/1300
40/130=400/1300
between 390/1300 and 400/1300
any number from 391/1300 to 399/1300 example 395/1300


3 0
3 years ago
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