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3 years ago

Thomas buys a skateboard that is 2 feet long. What is the length, in inches, of the skateboard?

Mathematics

1 answer:

Leviafan [203]3 years ago

5 0

1 foot is 12 inches

so 12 times 2
24

the answer is 24 inches

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Translation down 6 units

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Subtract -1 3/5 - ( -2 7/8) Enter your answer as a simplified fraction by filling in the boxes

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The answer is 51/40=1 and 11/40

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3 years ago

GEOMETRY HELP PLEASE

MissTica

An outside angle is equal to the sun of the two opposite inside angles.

The given inside angle is 75, the angle next to it is also 75 ( because there is a single line through the red arc, this means the angles are identical).

W = 75 + 75

W = 150 degrees.

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3 years ago

Using the numbers 1 to 9 (inclusive), without repeating any numbers, fill in the boxes to write two equivalent equations. The to

vovikov84 [41]

1The two equivalent equations will be

1. $y=\dfrac{-6}{4}x+10$

2. $3x+2y=5$

<h3>What is linear equation?</h3>

An equation between two variables that gives a straight line when plotted on a graph.

The required two equivalent equations are

$y=\dfrac{-6}{4}x+10$

$3x+2y=5$

The above equation has no repeating numbers and fulfill the criteria.

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8 0

3 years ago

David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin

Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let <em>A</em><em> </em>= 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

$\frac{a}{sin(A)} = \frac{b}{sin( B )} = \frac{c}{sin(C)}$

David's distance from the boat, <em>b</em>, is therefore;

$\frac{b}{sin( 32 )} = \frac{2000}{sin(78)}$

The angle subtended by the coastline, <em>C</em>, is therefore;

$b = \frac{2000}{sin(78)} \times sin( 32 ) = 1083.5$

David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

$\mathbf{ \frac{a}{sin( 70)} }= \frac{2000}{sin(78)}$

$a = \frac{2000}{sin(78)} \times sin( 70 ) = 1921.37$

Lacey's distance from the boat is 1921.37 feet

Part C

When <em>b </em>= 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

$\frac{1200}{sin(90)} = \frac{1018.17}{sin( B' )}$

${sin( B' )} = \frac{sin(90)}{1200} \times 1018.17$

The angle between the coastline and his view to the boat, <em>B'</em>, is therefore;

B' = arcsine (1018.17÷1200) = 58.05°

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2 years ago