Question

Perpendicular to y = 6x + 2; passing through the point (3,5).

Answer 1

Answer:

Step-by-step explanation:

y = 6x + 2

Slope = 6

A line perpendicular to this would have a negative reciprocal slope = $-\frac{1}{6}$

To solve for the y-intercept, plug the coordinates given into the question.

y = mx + b

5 =$-\frac{1}{6}$ (3) + b

5 = $-\frac{3}{6}$ + b

5 = $-\frac{1}{2}$ + b

b = 5 + $\frac{1}{2}$

b = $\frac{11}{2}$ or 5 $\frac{1}{2}$

So, your new slope-intercept line equation is

y = $-\frac{1}{6}$x + 5 $\frac{1}{2}$

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