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Mamont248 [21]
2 years ago
8

}{9}x - \frac{1}{3} = -1" alt="\frac{2}{9}x - \frac{1}{3} = -1" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
egoroff_w [7]2 years ago
7 0

\large \mathfrak{Solution : }

let's solve for x :

  • \dfrac{2}{9} x -  \dfrac{1}{3}  =  - 1

  • \dfrac{2}{9}  x =  - 1 +  \dfrac{1}{3}

  • \dfrac{2}{9} x =  \dfrac{ - 3 + 1}{3}

  • x =  \dfrac{ - 2}{3}  \times  \dfrac{9}{2}

  • x =  - 3

I hope it helped...

Oduvanchick [21]2 years ago
4 0

Answer:

x= -3

Step-by-step explanation:   both sides +1/3 so that the -1/3 gone

2/9x-1/3= -1

= 2/9x= -1+1/3

=2/9x= -2/3

=-3

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125 divided by 32 equals what
andreyandreev [35.5K]
32 × 2 = 68
32 × 3 = 96
32 × 4 = 128

So far we can conclude that the answer to your question lies somewhere between the numbers 3 and 4. To narrow down the answer some more, multiply 32 by 3.5 (a midway point between 3 and 4).

32 × 3.5 = 112
The number 112 tells us that the decimal we are looking for is higher than 3.5. (Because we need to get to 125, not 112.) Let's try some decimals between 3.5 and 4.

32 × 3.7 = 118.4
32 × 3.8 = 121.6
32 × 3.9 = 124.8
32 × 4 = 128

As we narrow down our answer, we can see that the number we are looking for lies between 3.9 and 4 on the number line. Now we need to start testing some decimals between 3.9 and 4. 

32 × 3.905 = 124.96
Again, use the number five as a "midway" point to decide if you should use numbers that are higher or lower than 3.905. In this case, we need to use numbers higher than 3.905.

32 × 3.906 = 124.992
32 × 3.907 = 125.024

We are getting even closer to our number now that we know the decimal is somewhere between 3.906 and 3.907.

32 × 3.9065 = 125.008
With our midway point we can see that our number lies between 3.906 and 3.9065. Let's try a quarter point to see where our number lies from there.

32 × 3.90625 = 125
And BINGO! We have found the answer to the question. To be rephrased, our answer can be put like this:

\frac{125}{32} = 3.90625
6 0
3 years ago
Solve it............<br>​
DedPeter [7]

Answer:

7

Step-by-step explanation:

1) for '8'; '3'; and '10':

8/2+3+3=10

2) for '2'; '5' and '11':

2/1+5+5=11

3) for '6'; '2' and '?':

6/2+2+2=7

8 0
3 years ago
Write a quadratic equation having the given numbers as solutions. -7 and -5
AlexFokin [52]

Answer:

x²+12x+35

Step-by-step explanation:

in factored form it would just be

(x+7)(x+5)=0

expand this

x²+12x+35=0

6 0
3 years ago
Please answer all this
Setler79 [48]

1/3=2/6

-1/6= -1/6

then I guessing you add them?

2/6+-1/6=1/6

6 0
2 years ago
Comelia and Christopher are arguing about Real Number (R) Sets. Comelia says that all Whole (W) numbers are Rational (Q) and Chr
eimsori [14]
<h3>Answer: Comelia is correct</h3>

====================================================

Explanation:

We're told that "Christopher  says that all Rational (Q) numbers are Whole (W)", which makes Christopher not correct. Some rational numbers are whole numbers. For instance, the number 7 = 7/1 is rational and it's a whole number as well.

However something like 1/2 is rational, but it's not a whole number. A whole number doesn't have any fractional or decimal part to it. It can be thought of the number of something.

Comelia is correct because all whole numbers are rational. If x is some whole number, then x = x/1 is rational as well. Replace x with any whole number you want. Her statement does not work in reverse as shown above.

When drawing a Venn diagram, the circle for "whole numbers" will be entirely inside the circle for "rational numbers", and not the other way around.

3 0
3 years ago
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