(2x² - 8x - 10) ÷ 2 = 0
x² - 4x - 5 = 0
x² + x - 5x - 5 = 0
x(x+1) - 5(x+1) = 0
(x+1)(x-5) = 0
x+1 = 0 or x-5 = 0
x = -1 or x= 5
S = {-1;5}
The answer is A A number line with a closed circle on 3-
The intersection is at (2,-1)
1. Definition of bisector
2. ASA congruence theorem or ASA Postulate
