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iris [78.8K]
3 years ago
8

How to answer this problem

Mathematics
1 answer:
lidiya [134]3 years ago
4 0
I dont know how to do that sorry
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Which equation matches the graph shown below?
MrRa [10]
Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:

y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5

To try to discard one of them, let us use the vertex, which is at x = -2.

With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.

Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.

Then, the answer is 2x^2 + 8x  -5
8 0
4 years ago
Plssss help in need of answers soon
vfiekz [6]
My guess is that you're doing the Law of Cosines? You have everything you need for that except the angle theta, which is the thing you need to find.  It's set up like this: (8)^2 = (10)^2 + (5)^2 -[2(10)(5)cos A]  I used A instead of theta. Doing that math, you have: 64 = 100 + 25 -[ 100 cos A]; 64 = 125 - 100 cos A;
-61 = - 100 cos A; -61 / -100 = cos A; .61 = cos A. Now use your inverse function on your calculator to find cos^-1(.61) and that equals 52.4
5 0
3 years ago
Read 2 more answers
Did I do this Math Right
kakasveta [241]
I cant answer if i dont know what math would you mind telling me what math

6 0
3 years ago
PLEASE HELP i need help
Helen [10]

Answer:

9)

Domain {-2, -1, 1}

Range {-4, -2, 2, 4}

7)

Domain {0, 1, 2}

Range {-2, 0, 2, 3}

6)

Domian {-4, -1, 1, 2}

Range {-7, -4, 2}

8 0
3 years ago
Combine the like terms to create an equivalent expression: <br><br>−4p+(−6p)
Y_Kistochka [10]

THE ANSWER IS -10P.

Step-by-step explanation:

USING BY MULTIPLICATION RULE.

minus × plus = minus

then minus × minus = plus.

so we add the 4p+6p= -10p.

why -10p is come it means THE BIGGER NUMBER SIGN IS MINUS. So it's comes -10p.

<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELP</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
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