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ira [324]
3 years ago
11

A letter in the word COURAGE is chosen at random, then a coin is tossed three times. How many outcomes are possible?

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

in the first one there are 7 outcomes

and in the second one there are hhh ,the,hth,tht, . h means head and t means tail

RideAnS [48]3 years ago
3 0

Answer:

I think about 10

Step-by-step explanation:

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Will mark brainliest lol​
BabaBlast [244]

Answer:

x=17

The angles are Vertical.

Step-by-step explanation:

6x17 equals 102. Then subtract 12 from 102 to get 90 degrees.

6(17)-12=90 degrees

3 0
3 years ago
Read 2 more answers
If 2x + 5y = 21 and x + y = 3, then what is the solution
Viefleur [7K]
2x+5y=21, x+y=3
y=3-x
2x+5y=21
2x+5(3-x) =21
2x+15-5x=21
2x-5x+15=21
-3x+15=21
-3x=21-15
-x=6/3
-x=2
x=-2

8 0
3 years ago
If f(x) = (5x^3 - 4)^4, then what is f '(x)?
vlabodo [156]
You apply the rule to put the exponent in front, and lower it by one. But since this is a nested expression, you apply it twice:

4*(5x^3-4)^3 * 3*5x^2 =

60x^2 (5x^3-4)^3
4 0
3 years ago
construct a 90% confidence interval of the population proportion using the giver information x=74 n=150
FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

<em>X</em> = 74

<em>n</em> = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

\hat p=\frac{X}{n}=\frac{74}{150}=0.493

Compute the critical value of <em>z</em> for 90% confidence level as follows:

z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645

*Use a <em>z</em>-table.

Compute the 90% confidence interval of the population proportion as follows:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

3 0
3 years ago
Please answer ASAP
labwork [276]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

A 12 cm cone with a dome on top of it that has an 8 cm diameter

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{Volume\:of\:the\:figure = 334.93\:cm^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

6 0
3 years ago
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