Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
<span> the equation of this circle is (x - 3)² + (y + 1)² = 4²</span>
BRO I DONT KNOW ANSWER EAST OR WEAST MY ANSWER IS BEST
Answer:
y = -4
x = -2
Step-by-step explanation:
Hi there...
y = 2x
y = -x - 6
Since why is equal to 2x, we can plug it in for y in the second equation. Here's what I mean...
2x = -x - 6
add x on both sides...
3x = -6
divide by 3 on both sides...
x = -2
Now, plug in x for y. Here's what I mean...
y = 2x
y = 2 (-2)
y = -4
Hope this helps :)
