Answer: 17.75
Step-by-step explanation:
The interquartile range(IQR) is the 3rd quartile - the 1st quartile.
How to get quartiles:
First get the median:
3.5, 10.4, 16, 21.7, 27.7
10.4, 16, 21.7
16
Then find the median of the first half of data(3.5, 10.4)
(3.5+10.4)/2 = 6.95
Then find the median of the last half of data(21.7, 27.7)
(21.7+27.7)/2 = 24.7
Then to get the IQR subtract 6.95 from 24.7 to get 17.75
Hope it helps <3
Answer:
- 1 = pentagon
- 2 = diamond
- 3 = square
- 5 = circle
- 6 = rectangle
- 7 = oval
- 8 = triangle
- 9 = hexagon
- 10 = trapezoid
Step-by-step explanation:
Each half of a hanger divides the total weight in half. The right-most vertical has a total weight of 80/16 = 5. It consists of a square and a diamond, and we know the square is 1 more than the diamond. That means 2 diamonds weigh 5 -1 = 4. A diamond weighs 2, and a square weighs 3. The other half of that balance is a circle, which weighs 5.
The total of a square and oval is 10, so the oval is 10 -3 = 7. The two trapezoids weigh 20, so each is 10.
The second vertical from the left is a circle and diamond which will weigh 5+2 = 7. That makes the sum of a pentagon and rectangle also be 7. The 7+7 = 14 below the square on the left branch makes the total of that branch be 14+3 = 17, which is also the sum of the triangle and hexagon.
The weight below the rectangle at top left is 17+17 = 34, and the weight of that entire branch is 40. Thus the rectangle is 40-34 = 6, which makes the pentagon 7-6 = 1.
We require the sum of the triangle and hexagon be 17, with the triangle being the smaller value, and both being 9 or less (the trapezoid is the only figure weighing more than 9). Hence the triangle is 8 and the hexagon is 9.
The weights are summarized in the answer section, above.
Answer: The area of shaded section is 491.07 cm²
Step-by-step explanation:
Given: Radius of the circle = 25 cm
Now as shown in figure the shaded region is a quadrant.
Therefore the central angle is 90°
Now as we know
Area of sector is given by
where r is radius and
is central angle
So we have
![Area = \dfrac{22}{7} \times (25)^2\times \dfrac{90^\circ}{360^\circ} \\\\\Rightarrow Area= \dfrac{22}{7} \times 625 \times \dfrac{1}{4} \\\\\Rightarrow Area= \dfrac{11}{7} \times 625 \times \dfrac{1}{2} = 491.07cm^2](https://tex.z-dn.net/?f=Area%20%3D%20%5Cdfrac%7B22%7D%7B7%7D%20%5Ctimes%20%2825%29%5E2%5Ctimes%20%5Cdfrac%7B90%5E%5Ccirc%7D%7B360%5E%5Ccirc%7D%20%5C%5C%5C%5C%5CRightarrow%20Area%3D%20%20%5Cdfrac%7B22%7D%7B7%7D%20%5Ctimes%20625%20%5Ctimes%20%5Cdfrac%7B1%7D%7B4%7D%20%5C%5C%5C%5C%5CRightarrow%20Area%3D%20%20%5Cdfrac%7B11%7D%7B7%7D%20%5Ctimes%20625%20%5Ctimes%20%5Cdfrac%7B1%7D%7B2%7D%20%3D%20491.07cm%5E2)
Hence, the area of shaded section is 491.07 cm²
The function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function that has vertex at (2, 6)
The options are:
f(x) = 2|x – 2| – 6
f(x) = 2|x – 2| + 6
f(x) = 2|x + 2| + 6
f(x) = 2|x + 2| – 6
As we know the vertex form of a quadratic function is given by:
f(x) = a(x - h)² + k
Similarly, mod function can be expressed as:
m(x) = a|x - h| + k
Here (h, k) is the vertex of a function.
In the function:
f(x) = 2|x – 2| + 6
The vertex of the function is (2, 6)
Thus, the function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
Learn more about the function here:
brainly.com/question/5245372
#SPJ1
Answer:
480m³
Step-by-step explanation:
The entire pool have the same depth which is 4metres
Since the pool is L shaped, we will find the volume of each part and add them together to get the volume of the entire pool.
Using the formula for calculating volume of a rectangular box
V = lwh
L is the length
w is the width
h is he height
For the first pool.
Length = 8m
Width = 6m
Height = 4m (depth)
Volume = 8×6×4
Volume = 192m³
For the other pool.
Length = 12m
Width = 6m
Height = 4m (depth)
Volume = 12×6×4
Volume = 288m³
Volume of the entire pool = 192+288 = 480m³