2/7 divided by 7/6 brainlyest on the line
1 answer:
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Answer:
(a) P = 2x + 2r + 2πr
(b) x = ½(P - 2r - 2πr)
(c) x = 123 feet
Step-by-step explanation:
See Attachment for sketch of the track
Solving for (a): Perimeter of the track
This is calculated by adding the perimeter of the rectangle to the 2 semicircles as follows.
P = Perimeter of Rectangle + Perimeter of 2 Semicircles
P = 2(x + r) + 2 * πr
[Where r is the radius of both semicircles]
Open bracket
P = 2x + 2r + 2πr
Solving for (b): Formula for x
P = 2x + 2r + 2πr
Make x the subject of formula
2x = P - 2r - 2πr
Divide both sides by 2
x = ½(P - 2r - 2πr)
Solving for (c): the value of x when r = 50 and P = 660
Substitute the given values in the formula in (b) above
x = ½(P - 2r - 2πr)
x = ½(660 - 2 * 50 - 2π * 50)
x = ½(660 - 100 - 100π)
x = ½(560 - 100π)
Take π as 3.14
x = ½(560 - 100 * 3.14)
x = ½(560 - 314)
x = ½ * 246
x = 123 feet
Answer:
Step-by-step explanation:
A) Let x represent acres of pumpkins, and y represent acres of corn. Here are the constraints:
x ≥ 2y . . . . . pumpkin acres are at least twice corn acres
x - y ≤ 10 . . . . the difference in acreage will not exceed 10
12 ≤ x ≤ 18 . . . . pumpkin acres will be between 12 and 18
0 ≤ y . . . . . the number of corn acres is non-negative
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B) If we assume the objective is to maximize profit, the profit function we want to maximize is ...
P = 360x +225y
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C) see below for a graph
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D) The profit for an acre of pumpkins is the highest, so the farmer should maximize that acreage. The constraint on the number of acres of pumpkins comes from the requirement that it not exceed 18 acres. Then additional profit is maximized by maximizing acres of corn, which can be at most half the number of acres of pumpkins, hence 9 acres.
So profit is maximized for 18 acres of pumpkins and 9 acres of corn.
Maximum profit is $360·18 +$225·9 = $8505.
