1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dominik [7]
3 years ago
6

Billy has 2.4 m of ribbon for crafts. He wants to share it evenly with 12 friends. How many centimeters of ribbon would 7 friend

s get? Can you please do like the DW (Draw write your answer)process.
Mathematics
2 answers:
Anarel [89]3 years ago
6 0

Answer:

140 cm for 7 friends and 20 cm or 12 friends

Step-by-step explanation:

We first have to change the 2.4 m to centimeters.

2.4 m x 100 = 240

then we do 240 ÷ 12 because they are 12 people they need to share it evenly with 12 people.  to make it easier we do..              For getting cm of 7 people

(24x10) ÷ 12 =                                                                   20 x 7 =  140

(24÷12) x 10 =

2 x 10

20 cm per friend

                                                                                          140 cm for 7 friends

It was 20 because there are 20 cm for 12 friends

Dimas [21]3 years ago
5 0

Answer: 34.29cm

Step-by-step explanation:

From the question, we are informed that Billy has 2.4 m of ribbon for crafts and that he wants to share it evenly with 12 friends.

The number of centimeters of ribbon that each of the 7 friends would get will be gotten by dividing 2.4m by 12. We can solve this by first converting 2.4meters to centimeters. This will be:

= 2.4meters = 2.4 × 100cm = 240 centimeters.

We then divide 240cm by 7. This will be:

= 240cm/7

= 34.29cm

You might be interested in
Which term is used to describe a number that makes a statement true?
frosja888 [35]
That is called the solution

factor is like 2 and 3 and 9 are factors of 18 because 2*9=18 and 3*6=18

inequality is like 3<4

product is multiplcation so like product of x and y is x times y



answer is solution
8 0
4 years ago
Partners A, B and C share the profit of a business deal. Partner A gets 1/6, Partner B gets 3/4 and Partner C gets €25. How much
34kurt
That is the answer. Hope it helps
8 0
3 years ago
A person who weighs 120 pounds on Earth weighs 20 pounds on the Moon. How much does a 93-pound person weigh on the Moon?
Andre45 [30]
If you would like to know how much does a 93-pound person weigh on the Moon, you can calculate this using the following steps:

120 pounds on the Earth ... 20 pounds on the Moon
93 pounds on the Earth ... x pounds on the Moon = ?

120 * x = 20 * 93      /120
x = 20 * 93 / 120
x = 15.5 pounds on the Moon

The correct result would be 15.5 pounds on the Moon.
5 0
3 years ago
Read 2 more answers
One number is 5 more than another the difference between their squares is 125 what are the numbers
storchak [24]
All these questions are so hard I still need answering with mine someone helppp
8 0
4 years ago
Whats y over 9 =y+2 over 3 in solving proportions NO LINKS THANKS
Eddi Din [679]

Answer:

y = - 3

Step-by-step explanation:

Given

\frac{y}{9} = \frac{y+2}{3} ( cross- multiply )

9(y + 2) = 3y ← distribute left side

9y + 18 = 3y ( subtract 3y from both sides )

6y + 18 = 0 ( subtract 18 from both sides )

6y = - 18 ( divide both sides by 6 )

y = - 3

6 0
3 years ago
Other questions:
  • It’s not 99/130 MARK BRAINLIEST
    15·1 answer
  • 2/x=6/2 solve for x.
    9·2 answers
  • One ounce is about the same as 0.06 pound. What is 0.06 written as a fraction?
    12·2 answers
  • Show your work<br> 4(2x - 6) = 10x - 6
    5·2 answers
  • What is the product of 2p + q and -3q - 6p + 1
    11·1 answer
  • What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i?
    9·2 answers
  • Question 4 (True/False Worth 4 points)
    13·2 answers
  • What is the equation of the line
    11·1 answer
  • Energy = mass x (speed of light)²
    7·1 answer
  • 4x +5 =x+8 please show work
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!