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Firdavs [7]
3 years ago
5

This is easy but I really struggle with maths can someone help please urgent

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0
The value fo k is \frac{13}{2}. This is because c, the constant, is the y-intercept. The graph shows where the line intersects the y-axis, which is -3. So you substitute -3 with c. To find the value of k, plug in the coordinate with the x and y values and then solve for k.
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Write an expression for the calculation triple 4 and then add 7 times 7
ira [324]
The answer should be 61
4×3=12
7×7=49
12+49=61
4×3 + (7×7)
7 0
3 years ago
Read 2 more answers
The length of a rectangle is 2 more than 3 times the width. If the perimeter is 100, find the length and width of the rectangle.
Neko [114]
L=17.49635531
W=5.715476066

100 = L X W
L = 2+ 3W 
Insert the L equation into the 1st equation, 2+ 3W x W = 100 
<span>2+ 3W x W = 100
</span>-2                    -2
3W X W = 98
3W^2 = 98
Divide both sides by 3
W^2 = 32.66
Square root both sides
now you have the Width, plug the width into the L X W = 100 equation, then divide 100 by the width, and now you have the length.
6 0
4 years ago
Read 2 more answers
Can you solve this in a good way please
IRINA_888 [86]

Answer:

5/2 x^2y^2

Step-by-step explanation:

( x^2 - 3/5y^2)^2 + (3/4 x^2 + 4/5 y^2)^2 - (5/4x^2 - y^2)^2

=  x^4 - 6/5x^2y^2 + 9/25y^4 + 9/16x^4 + 6/5x^2y^2 + 16/25y^4 - ( 25/16x^4

- 5/2x^2y^2 + y^4)

Distributing the negative over the parentheses:-

=  x^4 - 6/5x^2y^2 + 9/25y^4 + 9/16x^4 + 6/5x^2y^2 + 16/25y^4

- 25/16x^4

+  5/2x^2y^2 - y^4

Bringing like terms together

x^4 + 9/16x^4 - 25/16x^4 - 6/5x^2y^2 + 6/5x^2y^2 +  5/2x^2y^2   +  16/25y^4 + 9/25y^4

- y^4  

Adding like terms:-

= 5/2 x^2y^2  Answer

8 0
3 years ago
I really do need help solving this equation
strojnjashka [21]

Answer:

D

Step-by-step explanation:

3/5 = 0.6

75% = .75

0.8, 0.75, 0.6, 0.56

8 0
3 years ago
Can you Factor 42c2 +24c=
tia_tia [17]
You will have to factor 6c out of 42c2+24c. Then the answer will be 6c(7c+4).
4 0
4 years ago
Read 2 more answers
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