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Mumz [18]
3 years ago
14

Can you solve this in a good way please

Mathematics
1 answer:
IRINA_888 [86]3 years ago
8 0

Answer:

5/2 x^2y^2

Step-by-step explanation:

( x^2 - 3/5y^2)^2 + (3/4 x^2 + 4/5 y^2)^2 - (5/4x^2 - y^2)^2

=  x^4 - 6/5x^2y^2 + 9/25y^4 + 9/16x^4 + 6/5x^2y^2 + 16/25y^4 - ( 25/16x^4

- 5/2x^2y^2 + y^4)

Distributing the negative over the parentheses:-

=  x^4 - 6/5x^2y^2 + 9/25y^4 + 9/16x^4 + 6/5x^2y^2 + 16/25y^4

- 25/16x^4

+  5/2x^2y^2 - y^4

Bringing like terms together

x^4 + 9/16x^4 - 25/16x^4 - 6/5x^2y^2 + 6/5x^2y^2 +  5/2x^2y^2   +  16/25y^4 + 9/25y^4

- y^4  

Adding like terms:-

= 5/2 x^2y^2  Answer

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You should find the slope using (y2 - y1) / (x2 - x1) = m

m = (18 - 0) / (10 - (-1))

m= 18 / 11

Therefore the slope is 18/11

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A   0   1       2      3

B   0   1.5    3     4.5

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4 years ago
One root of a third degree polynomial function f(x) is –5 + 2i. Which statement describes the number and nature of all roots for
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QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
masha68 [24]

The central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BD)/18.

Given that BD is diameter of the circle and angle BAC is 100°.

We are required to find the central angle, major arc, minor arc, m BEC, BC.

Angle is basically finding out the intensity of inclination of something on the surface.

In the circle central angles are many like BAC and CAD. We can write CAD as DAC also.

Major arc of a circle is that arc whose length is larger than all other arcs in the circle.

In our circle the major arc is arc BED.

Minor arc of a circle is that arc whose length is smaller.

In our circle the minor arc is arc ADC.

We know that arc's length is 2πr(Θ/360)

In this way BC=2π*(BD/2)*100/360

=(5π*BD)/18

We cannot find angle BEC.

Hence the central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BA)/18.

Learn more about angles at brainly.com/question/25716982

#SPJ1

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