The value of y is 5
<h3>How to determine the value </h3>
From the given line, it can be concluded that:
The segment RT is divided into RS and ST
But we have the following parameters
The length of the sides are:
Since RT is RS added to ST:
We have;
RT = RS + ST
substitute the values
43 = 4y + 4 + 3y + 4
collect like terms
43 = 4y + 3y + 4 + 4
Add like terms
43 = 7y + 8
43 = 7y + 8
Make '7y' subject of formula
7y = 43 - 8
7y = 35
Make 'y' the subject of formula
y = 35/ 7
y = 5
Thus, the value of y is 5
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Original Ratio of 1 in = 7 ft so 3 in = 21 ft
Now, New ratio 1 in = x ft so 3 in = 27ft
1/x = 3/27
cross multiply a/b = c/d ad = bc
1/x = 3/27
3x = 27
x = 9
1 in represents 9 ft
<h3>
Answer: 3 m/s^2</h3>
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According to Newton's Second Law, we know that
F = m*a
where F is the force applied, m is the mass and 'a' is the acceleration.
We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.
Plug in F = 35 and a = 5 to find m
F = ma
35 = m*5
35/5 = m
7 = m
m = 7
The object has a mass of 7 kg
Our equation F = ma updates to F = 7a
Now plug in the force F = 21 to find 'a'
F = 7a
21 = 7a
21/7 = a
3 = a
a = 3
The acceleration will be 3 m/s^2
Notice how a smaller force applied means that the acceleration has also gone down as well.
