X will be used for the value of money she earned that week.
H represents the normal hours she worked.
D represents the number of days.
Y will represent the hours on the holiday.
Since she would be getting time and a half on the holiday, you would need to find how much time and a half pay would be first.
Time and a half = 5.50(1/2) + 5.50 = $8.25/hr for the day or holiday only.
X = 5.50(H)(D) + 8.25(Y)
Plug in your numbers
X = 5.50(7)(5) + 8.25(4)
X = 192.5 + 33
She made $225.5 that week.
Answer:
we get 
Step-by-step explanation:
We are given: 
We need to find 
Note: Since question is not clear, I am assuming that we need to find 
Solving:

We know that 
Using formula and simplifying

So, we get 
Answer:
a. 52%
b. 40%
Step-by-step explanation:
Let A represents the event of raining on Monday and B represents the event of raining in Tuesday,
Then according to the question,
P(A) = 20% = 0.2,
P(B) = 40% = 0.4,
Here, A and B are independent events,
So, P(A∩B) = P(A) × P(B),
⇒ P(A∩B) = 0.2 × 0.4 = 0.08
We know that,
P(A∪B) = P(A) + P(B) - P(A∩B)
a. The probability it rains on Monday or Tuesday, P(A∪B) = 0.2 + 0.4 - 0.08
= 0.52
= 52%
b. The conditional probability it rains on Tuesday given that it rained on Monday,

Your answer is xy^2(4+3y). if u need anything else just tell meh