Question

1. If x=3-√3, prove that x² +36 x² = x²

Answer 1

Answer:

we get $x^2=12-6\sqrt{3}$

Step-by-step explanation:

We are given: $x=3-\sqrt{3}$

We need to find $x^2$

Note: Since question is not clear, I am assuming that we need to find $x^2$

Solving:

$x=3-\sqrt{3} \\Taking \ square \ on \ both \ sides\\x^2=(3-\sqrt{3})^2$

We know that $(a-b)^2= a^2-2ab+b^2$

Using formula and simplifying

$x^2=(3)^2-2(3)(\sqrt{3})+(\sqrt{3})^2\\x^2=9-6\sqrt{3} +3\\x^2=12-6\sqrt{3}$

So, we get $x^2=12-6\sqrt{3}$