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Bumek [7]
3 years ago
5

What is the relationship between multiplying and factoring

Mathematics
2 answers:
STatiana [176]3 years ago
5 0

Answer and explanation;

-When you factor a number, you write it as a product - a list of numbers which, when multiplied, give you the original number.

-Multiplying is making a number bigger by adding itself to itself a certain number of times and factoring is the opposite, taking away a certain number from itself.

GREYUIT [131]3 years ago
4 0
<span>The fundamental idea of multiplying is <em>repeated addition</em>. For example:

3 \times 5 = 15

By taking the number five and add it itself three times we have:

3 \times 5 = 5+5+5=15

In contrast, let's take the number three and add it itself five times, so: 

3 \times 5 = 3+3+3+3+3=15.

Both 3 and 5 are called factors that are numbers. We can multiply them to get another number. Multiplying can also be expressed like this:

(a+b)(a-b)

So you have the factors:

(a+b) \ and\ (a-b) 

You can even write any multiplication as the product of factors. On the other hands, factoring shows that you can write any nth-degree polynomial as the product of linear factors, so:

f(x)=(x-a)(x-b)(x-c)

To conclude the <em>relationship</em> between both concepts is the product of factors.</span>
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One-half squared is one-fourth.

Step-by-step explanation:

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What is 5/20 in its simplest form
notsponge [240]
5/20 in simplest form 

1) 5/20 can be divided by 5 

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A photography studio charges $50 that includes a sitting fee and 6 prints. Luigi increased his order to 11 prints and paid $65.
Effectus [21]

Answer:

Sitting fee - 32$

Step-by-step explanation:

This is a system of equations(let x represent the sitting fee)

x+6y=50

x+11y=65

You want to isolate the x variable - x+6y-6y=50-6y ; x = 50-6y

Input this into the 2nd equation: 50-6y+11y=65 ; 50+5y=65

Subtract 50 from both sides. 5y=15 (Divided 5y on both sides) ; y=3

Now that y = 3 input this into any equation I choose the 1st one.

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Prove: 32 + 6(3) = 50 ; 32+18 = 50 ; 50 = 50 True



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3 years ago
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