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3 years ago

Determine whether the graph is that of a function. An open circle indicates that the point does not belong to the graph.

Mathematics

1 answer:

Paladinen [302]3 years ago

6 0

Answer:

yes it is not a function because when a straight line is drawn it cuts the circles two points .

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Select the correct answer.

timama [110]

Answer:

Edison will be paid $15,112 for the first three months.

Step-by-step explanation:

Edison receives an annual fixed pay = $45,448.

Monthly pay = 45,448/12 = $3787.33

3-month salary = $3787.33 *3 = $11.362

Commission = 15%

Total sale = $25,000 for the first 3 months.

Commission amount = 25,000*0.15 = $3750

Therefore, total pay that Edison received during first 3 months= salary + commission

= $11,362 + $3750

= $15,112

4 0

3 years ago

Log 10,000 = ?<br><br><br>This is such a stupid question, sorry lol

Lyrx [107]

Answer:

Log 10,000 = 4

hope it helps!

6 0

3 years ago

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What is the distance between points F(6,4) and G(14,19)?

Marrrta [24]

Answer: I put a photo of what I did

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3 years ago

A basketball player makes 30% of her foul shots. she shoots 5 foul shots. you are interested in the number of shots that she mak

vampirchik [111]

This would be a binomial model, since there is a fixed number of trials, the probabilities are independent and there are only two choices (either the shot is made or missed).

5 0

3 years ago

The graph of the equation 2x2 + xy + y2 = 4 is the tilted ellipse pictured below; i.e. the points (x,y) in the plane that satisf

mihalych1998 [28]

Answer:

The slope of tangent at point (1,-2) is $\frac{2}{3}$ .

Step-by-step explanation:

The given equation of ellipse is

$2x^2+xy+y^2=4$

Differentiate both sides with respect to x.

$\frac{d}{dx}(2x^2+xy+y^2)=\frac{d}{dx}(4)$

$\frac{d}{dx}(2x^2)\frac{d}{dx}(xy)+\frac{d}{dx}(y^2)=\frac{d}{dx}(4)$

$4x+x\frac{dy}{dx}+y+2y\frac{dy}{dx}=0$

$(4x+y)+(x+2y)\frac{dy}{dx}=0$

$\frac{dy}{dx}=-\frac{4x+y}{x+2y}$

Calculate the value of \frac{dy}{dx} at (1,-2).

$\frac{dy}{dx}_{(1,-2)}=-\frac{4(1)+(-2)}{(1)+2(-2)}$

$\frac{dy}{dx}_{(1,-2)}=-\frac{2}{-3}$

$\frac{dy}{dx}_{(1,-2)}=\frac{2}{3}$

Therefore the slope of tangent at point (1,-2) is $\frac{2}{3}$ .

3 0

3 years ago

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